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122122121597813 is a prime number
BaseRepresentation
bin11011110001000111000101…
…101011010101001101110101
3121000101202112121221211110202
4123301013011223111031311
5112001322101112112223
61111422043403330245
734503014006144051
oct3361070553251565
9530352477854422
10122122121597813
1135a03778a19a37
1211844103520985
13531b0b3588a0c
142222a56934c61
15e1ba239ba428
hex6f11c5ad5375

122122121597813 has 2 divisors, whose sum is σ = 122122121597814. Its totient is φ = 122122121597812.

The previous prime is 122122121597753. The next prime is 122122121597837. The reversal of 122122121597813 is 318795121221221.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 95283329097124 + 26838792500689 = 9761318^2 + 5180617^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-122122121597813 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (122122121537813) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61061060798906 + 61061060798907.

It is an arithmetic number, because the mean of its divisors is an integer number (61061060798907).

Almost surely, 2122122121597813 is an apocalyptic number.

It is an amenable number.

122122121597813 is a deficient number, since it is larger than the sum of its proper divisors (1).

122122121597813 is an equidigital number, since it uses as much as digits as its factorization.

122122121597813 is an evil number, because the sum of its binary digits is even.

The product of its digits is 241920, while the sum is 47.

The spelling of 122122121597813 in words is "one hundred twenty-two trillion, one hundred twenty-two billion, one hundred twenty-one million, five hundred ninety-seven thousand, eight hundred thirteen".