Base | Representation |
---|---|
bin | 1011000110111000000010… |
… | …1100010000011011110111 |
3 | 1121020112020121211011212212 |
4 | 2301232000230100123313 |
5 | 3100043203240422311 |
6 | 41550243240404035 |
7 | 2400225233415011 |
oct | 261560054203367 |
9 | 47215217734785 |
10 | 12212751107831 |
11 | 398944268404a |
12 | 1452ab577661b |
13 | 6a7871668381 |
14 | 30315935b1b1 |
15 | 162a35a30c8b |
hex | b1b80b106f7 |
12212751107831 has 2 divisors, whose sum is σ = 12212751107832. Its totient is φ = 12212751107830.
The previous prime is 12212751107819. The next prime is 12212751107833. The reversal of 12212751107831 is 13870115721221.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12212751107831 - 210 = 12212751106807 is a prime.
It is a super-2 number, since 2×122127511078312 (a number of 27 digits) contains 22 as substring.
Together with 12212751107833, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12212751107833) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6106375553915 + 6106375553916.
It is an arithmetic number, because the mean of its divisors is an integer number (6106375553916).
Almost surely, 212212751107831 is an apocalyptic number.
12212751107831 is a deficient number, since it is larger than the sum of its proper divisors (1).
12212751107831 is an equidigital number, since it uses as much as digits as its factorization.
12212751107831 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 47040, while the sum is 41.
The spelling of 12212751107831 in words is "twelve trillion, two hundred twelve billion, seven hundred fifty-one million, one hundred seven thousand, eight hundred thirty-one".
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