Base | Representation |
---|---|
bin | 111000110111110000… |
… | …1010110111100111111 |
3 | 102200020110022220102012 |
4 | 1301233201112330333 |
5 | 4000110301200111 |
6 | 132034503521435 |
7 | 11552332502402 |
oct | 1615741267477 |
9 | 380213286365 |
10 | 122130100031 |
11 | 47882291875 |
12 | 1b80515927b |
13 | b6945b38a4 |
14 | 5ca81c9d39 |
15 | 329beb648b |
hex | 1c6f856f3f |
122130100031 has 2 divisors, whose sum is σ = 122130100032. Its totient is φ = 122130100030.
The previous prime is 122130100021. The next prime is 122130100033. The reversal of 122130100031 is 130001031221.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 122130100031 - 26 = 122130099967 is a prime.
It is a super-2 number, since 2×1221301000312 (a number of 23 digits) contains 22 as substring.
Together with 122130100033, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 122130099979 and 122130100015.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (122130100033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61065050015 + 61065050016.
It is an arithmetic number, because the mean of its divisors is an integer number (61065050016).
Almost surely, 2122130100031 is an apocalyptic number.
122130100031 is a deficient number, since it is larger than the sum of its proper divisors (1).
122130100031 is an equidigital number, since it uses as much as digits as its factorization.
122130100031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36, while the sum is 14.
Adding to 122130100031 its reverse (130001031221), we get a palindrome (252131131252).
The spelling of 122130100031 in words is "one hundred twenty-two billion, one hundred thirty million, one hundred thousand, thirty-one".
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