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1221311423113 is a prime number
BaseRepresentation
bin10001110001011011110…
…101010110001010001001
311022202102021220120112121
4101301123311112022021
5130002221211014423
62333021314211241
7154144143544645
oct21613365261211
94282367816477
101221311423113
11430a56505771
12178846883b21
138b227899b42
144317ca65c25
1521b80b5145d
hex11c5bd56289

1221311423113 has 2 divisors, whose sum is σ = 1221311423114. Its totient is φ = 1221311423112.

The previous prime is 1221311423107. The next prime is 1221311423119. The reversal of 1221311423113 is 3113241131221.

It is a balanced prime because it is at equal distance from previous prime (1221311423107) and next prime (1221311423119).

It can be written as a sum of positive squares in only one way, i.e., 742790593609 + 478520829504 = 861853^2 + 691752^2 .

It is a cyclic number.

It is not a de Polignac number, because 1221311423113 - 29 = 1221311422601 is a prime.

It is a super-2 number, since 2×12213114231132 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1221311423119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610655711556 + 610655711557.

It is an arithmetic number, because the mean of its divisors is an integer number (610655711557).

Almost surely, 21221311423113 is an apocalyptic number.

It is an amenable number.

1221311423113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1221311423113 is an equidigital number, since it uses as much as digits as its factorization.

1221311423113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 864, while the sum is 25.

Adding to 1221311423113 its reverse (3113241131221), we get a palindrome (4334552554334).

The spelling of 1221311423113 in words is "one trillion, two hundred twenty-one billion, three hundred eleven million, four hundred twenty-three thousand, one hundred thirteen".