Base | Representation |
---|---|
bin | 1011000110111001101110… |
… | …1000001011010100011010 |
3 | 1121020120102010011212010112 |
4 | 2301232123220023110122 |
5 | 3100100114433220010 |
6 | 41550400142444322 |
7 | 2400242361552224 |
oct | 261563350132432 |
9 | 47216363155115 |
10 | 12213203023130 |
11 | 398965478876a |
12 | 1453000b936a2 |
13 | 6a7914185a85 |
14 | 30319d397414 |
15 | 162a6054ba05 |
hex | b1b9ba0b51a |
12213203023130 has 32 divisors (see below), whose sum is σ = 22373798097600. Its totient is φ = 4798736371072.
The previous prime is 12213203023129. The next prime is 12213203023171. The reversal of 12213203023130 is 3132030231221.
12213203023130 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 12213203023096 and 12213203023105.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7310195 + ... + 8824134.
It is an arithmetic number, because the mean of its divisors is an integer number (699181190550).
Almost surely, 212213203023130 is an apocalyptic number.
12213203023130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
12213203023130 is a deficient number, since it is larger than the sum of its proper divisors (10160595074470).
12213203023130 is a wasteful number, since it uses less digits than its factorization.
12213203023130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16135678.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 12213203023130 its reverse (3132030231221), we get a palindrome (15345233254351).
The spelling of 12213203023130 in words is "twelve trillion, two hundred thirteen billion, two hundred three million, twenty-three thousand, one hundred thirty".
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