Base | Representation |
---|---|
bin | 11011110001010000100110… |
… | …001101100001111100111011 |
3 | 121000102201220010221210120021 |
4 | 123301100212031201330323 |
5 | 112002004003231011303 |
6 | 1111430452432511311 |
7 | 34503525006442231 |
oct | 3361204615417473 |
9 | 530381803853507 |
10 | 122132331110203 |
11 | 35a08037a23787 |
12 | 118460926ab537 |
13 | 531c04c7b10cb |
14 | 2223344834951 |
15 | e1be1ee60ebd |
hex | 6f1426361f3b |
122132331110203 has 2 divisors, whose sum is σ = 122132331110204. Its totient is φ = 122132331110202.
The previous prime is 122132331110201. The next prime is 122132331110263. The reversal of 122132331110203 is 302011133231221.
It is a weak prime.
It is an emirp because it is prime and its reverse (302011133231221) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 122132331110203 - 21 = 122132331110201 is a prime.
Together with 122132331110201, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (122132331110201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61066165555101 + 61066165555102.
It is an arithmetic number, because the mean of its divisors is an integer number (61066165555102).
Almost surely, 2122132331110203 is an apocalyptic number.
122132331110203 is a deficient number, since it is larger than the sum of its proper divisors (1).
122132331110203 is an equidigital number, since it uses as much as digits as its factorization.
122132331110203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 122132331110203 its reverse (302011133231221), we get a palindrome (424143464341424).
The spelling of 122132331110203 in words is "one hundred twenty-two trillion, one hundred thirty-two billion, three hundred thirty-one million, one hundred ten thousand, two hundred three".
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