Base | Representation |
---|---|
bin | 1011000110111010001000… |
… | …1101010110011000111100 |
3 | 1121020120200210221011101121 |
4 | 2301232202031112120330 |
5 | 3100100331214243400 |
6 | 41550415125120324 |
7 | 2400245202163315 |
oct | 261564215263074 |
9 | 47216623834347 |
10 | 12213313431100 |
11 | 3989701038921 |
12 | 1453031b590a4 |
13 | 6a7931001a32 |
14 | 3031adcd760c |
15 | 162a6a0aa21a |
hex | b1ba235663c |
12213313431100 has 36 divisors (see below), whose sum is σ = 26504125849600. Its totient is φ = 4885097592960.
The previous prime is 12213313431061. The next prime is 12213313431113. The reversal of 12213313431100 is 113431331221.
12213313431100 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (25).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 683580 + ... + 4989379.
Almost surely, 212213313431100 is an apocalyptic number.
12213313431100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
12213313431100 is an abundant number, since it is smaller than the sum of its proper divisors (14290812418500).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12213313431100 is a wasteful number, since it uses less digits than its factorization.
12213313431100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5694502 (or 5694495 counting only the distinct ones).
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 12213313431100 its reverse (113431331221), we get a palindrome (12326744762321).
The spelling of 12213313431100 in words is "twelve trillion, two hundred thirteen billion, three hundred thirteen million, four hundred thirty-one thousand, one hundred".
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