Base | Representation |
---|---|
bin | 111000111000000011… |
… | …1010001110011011101 |
3 | 102200021011000221001111 |
4 | 1301300013101303131 |
5 | 4000120322243123 |
6 | 132035500542021 |
7 | 11552513133166 |
oct | 1616007216335 |
9 | 380234027044 |
10 | 122140040413 |
11 | 47887961166 |
12 | 1b808551911 |
13 | b696684281 |
14 | 5ca965676d |
15 | 329cccb90d |
hex | 1c701d1cdd |
122140040413 has 2 divisors, whose sum is σ = 122140040414. Its totient is φ = 122140040412.
The previous prime is 122140040381. The next prime is 122140040417. The reversal of 122140040413 is 314040041221.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 105350878084 + 16789162329 = 324578^2 + 129573^2 .
It is a cyclic number.
It is not a de Polignac number, because 122140040413 - 25 = 122140040381 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (122140040417) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61070020206 + 61070020207.
It is an arithmetic number, because the mean of its divisors is an integer number (61070020207).
Almost surely, 2122140040413 is an apocalyptic number.
It is an amenable number.
122140040413 is a deficient number, since it is larger than the sum of its proper divisors (1).
122140040413 is an equidigital number, since it uses as much as digits as its factorization.
122140040413 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 768, while the sum is 22.
Adding to 122140040413 its reverse (314040041221), we get a palindrome (436180081634).
The spelling of 122140040413 in words is "one hundred twenty-two billion, one hundred forty million, forty thousand, four hundred thirteen".
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