Search a number
-
+
12214403231 is a prime number
BaseRepresentation
bin10110110000000100…
…10000000010011111
31011112020112222021212
423120002100002133
5200003341400411
65340005015035
7611453500022
oct133002200237
934466488255
1012214403231
1151a8791a28
12244a6b447b
1311c86c2944
1483c2ad1b9
154b74c268b
hex2d809009f

12214403231 has 2 divisors, whose sum is σ = 12214403232. Its totient is φ = 12214403230.

The previous prime is 12214403209. The next prime is 12214403233. The reversal of 12214403231 is 13230441221.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12214403231 is a prime.

It is a super-2 number, since 2×122144032312 (a number of 21 digits) contains 22 as substring.

Together with 12214403233, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 12214403197 and 12214403206.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12214403233) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6107201615 + 6107201616.

It is an arithmetic number, because the mean of its divisors is an integer number (6107201616).

Almost surely, 212214403231 is an apocalyptic number.

12214403231 is a deficient number, since it is larger than the sum of its proper divisors (1).

12214403231 is an equidigital number, since it uses as much as digits as its factorization.

12214403231 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 12214403231 its reverse (13230441221), we get a palindrome (25444844452).

The spelling of 12214403231 in words is "twelve billion, two hundred fourteen million, four hundred three thousand, two hundred thirty-one".