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12221013121319 is a prime number
BaseRepresentation
bin1011000111010110110100…
…1001010101100100100111
31121021022120102020221201102
42301311231021111210213
53100212113324340234
641554131140150315
72400640045363622
oct261655511254447
947238512227642
1012221013121319
1139919a2340072
12145462069839b
136a858a269052
1430370074adb9
15162d6b034c7e
hexb1d6d255927

12221013121319 has 2 divisors, whose sum is σ = 12221013121320. Its totient is φ = 12221013121318.

The previous prime is 12221013121301. The next prime is 12221013121337. The reversal of 12221013121319 is 91312131012221.

It is a balanced prime because it is at equal distance from previous prime (12221013121301) and next prime (12221013121337).

It is a cyclic number.

It is not a de Polignac number, because 12221013121319 - 236 = 12152293644583 is a prime.

It is a super-2 number, since 2×122210131213192 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12221013121291 and 12221013121300.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12221013120319) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6110506560659 + 6110506560660.

It is an arithmetic number, because the mean of its divisors is an integer number (6110506560660).

Almost surely, 212221013121319 is an apocalyptic number.

12221013121319 is a deficient number, since it is larger than the sum of its proper divisors (1).

12221013121319 is an equidigital number, since it uses as much as digits as its factorization.

12221013121319 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 29.

The spelling of 12221013121319 in words is "twelve trillion, two hundred twenty-one billion, thirteen million, one hundred twenty-one thousand, three hundred nineteen".