Base | Representation |
---|---|
bin | 1011000111010111001001… |
… | …0101001011010010010001 |
3 | 1121021022210110221111010012 |
4 | 2301311302111023102101 |
5 | 3100212303112022433 |
6 | 41554143524444305 |
7 | 2400642152651054 |
oct | 261656225132221 |
9 | 47238713844105 |
10 | 12221100110993 |
11 | 3991a37455764 |
12 | 1454645849695 |
13 | 6a85a22a5a27 |
14 | 30370c112a9b |
15 | 162d739b9848 |
hex | b1d7254b491 |
12221100110993 has 2 divisors, whose sum is σ = 12221100110994. Its totient is φ = 12221100110992.
The previous prime is 12221100110987. The next prime is 12221100111131. The reversal of 12221100110993 is 39901100112221.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11973620725264 + 247479385729 = 3460292^2 + 497473^2 .
It is a cyclic number.
It is not a de Polignac number, because 12221100110993 - 24 = 12221100110977 is a prime.
It is not a weakly prime, because it can be changed into another prime (12221100140993) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6110550055496 + 6110550055497.
It is an arithmetic number, because the mean of its divisors is an integer number (6110550055497).
Almost surely, 212221100110993 is an apocalyptic number.
It is an amenable number.
12221100110993 is a deficient number, since it is larger than the sum of its proper divisors (1).
12221100110993 is an equidigital number, since it uses as much as digits as its factorization.
12221100110993 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1944, while the sum is 32.
The spelling of 12221100110993 in words is "twelve trillion, two hundred twenty-one billion, one hundred million, one hundred ten thousand, nine hundred ninety-three".
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