Base | Representation |
---|---|
bin | 11011110010011001110111… |
… | …110101110000001010001111 |
3 | 121000201020222102012112110211 |
4 | 123302121313311300022033 |
5 | 112004301122031114413 |
6 | 1111530543554543251 |
7 | 34512311520233653 |
oct | 3362316765601217 |
9 | 530636872175424 |
10 | 122211010019983 |
11 | 35a38442138165 |
12 | 1185938bb97b27 |
13 | 53265ab005521 |
14 | 2227089d5ca63 |
15 | e1dec747583d |
hex | 6f2677d7028f |
122211010019983 has 2 divisors, whose sum is σ = 122211010019984. Its totient is φ = 122211010019982.
The previous prime is 122211010019981. The next prime is 122211010019993. The reversal of 122211010019983 is 389910010112221.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 122211010019983 - 21 = 122211010019981 is a prime.
Together with 122211010019981, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (122211010019981) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61105505009991 + 61105505009992.
It is an arithmetic number, because the mean of its divisors is an integer number (61105505009992).
Almost surely, 2122211010019983 is an apocalyptic number.
122211010019983 is a deficient number, since it is larger than the sum of its proper divisors (1).
122211010019983 is an equidigital number, since it uses as much as digits as its factorization.
122211010019983 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15552, while the sum is 40.
The spelling of 122211010019983 in words is "one hundred twenty-two trillion, two hundred eleven billion, ten million, nineteen thousand, nine hundred eighty-three".
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