Base | Representation |
---|---|
bin | 1011000111010111001011… |
… | …1010111101000101011101 |
3 | 1121021022211011120121220101 |
4 | 2301311302322331011131 |
5 | 3100212313130424201 |
6 | 41554144521021101 |
7 | 2400642333065506 |
oct | 261656272750535 |
9 | 47238734517811 |
10 | 12221110014301 |
11 | 3991a41aaa211 |
12 | 1454649024791 |
13 | 6a85a4362586 |
14 | 30370d56dbad |
15 | 162d747c3d01 |
hex | b1d72ebd15d |
12221110014301 has 2 divisors, whose sum is σ = 12221110014302. Its totient is φ = 12221110014300.
The previous prime is 12221110014259. The next prime is 12221110014367. The reversal of 12221110014301 is 10341001112221.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11728748175076 + 492361839225 = 3424726^2 + 701685^2 .
It is a cyclic number.
It is not a de Polignac number, because 12221110014301 - 211 = 12221110012253 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12221110014371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6110555007150 + 6110555007151.
It is an arithmetic number, because the mean of its divisors is an integer number (6110555007151).
Almost surely, 212221110014301 is an apocalyptic number.
It is an amenable number.
12221110014301 is a deficient number, since it is larger than the sum of its proper divisors (1).
12221110014301 is an equidigital number, since it uses as much as digits as its factorization.
12221110014301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 12221110014301 its reverse (10341001112221), we get a palindrome (22562111126522).
The spelling of 12221110014301 in words is "twelve trillion, two hundred twenty-one billion, one hundred ten million, fourteen thousand, three hundred one".
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