Search a number
-
+
122214241033 is a prime number
BaseRepresentation
bin111000111010010001…
…0010101001100001001
3102200110022122201011121
41301310202111030021
54000243321203113
6132051111155241
711554403623423
oct1616442251411
9380408581147
10122214241033
1147915831195
121b829375b21
13b6a8b63a71
145cb544d813
1532a4586e8d
hex1c74895309

122214241033 has 2 divisors, whose sum is σ = 122214241034. Its totient is φ = 122214241032.

The previous prime is 122214241031. The next prime is 122214241043. The reversal of 122214241033 is 330142412221.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 100607592969 + 21606648064 = 317187^2 + 146992^2 .

It is a cyclic number.

It is not a de Polignac number, because 122214241033 - 21 = 122214241031 is a prime.

It is a super-2 number, since 2×1222142410332 (a number of 23 digits) contains 22 as substring.

Together with 122214241031, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 122214240989 and 122214241007.

It is not a weakly prime, because it can be changed into another prime (122214241031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61107120516 + 61107120517.

It is an arithmetic number, because the mean of its divisors is an integer number (61107120517).

Almost surely, 2122214241033 is an apocalyptic number.

It is an amenable number.

122214241033 is a deficient number, since it is larger than the sum of its proper divisors (1).

122214241033 is an equidigital number, since it uses as much as digits as its factorization.

122214241033 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 122214241033 its reverse (330142412221), we get a palindrome (452356653254).

The spelling of 122214241033 in words is "one hundred twenty-two billion, two hundred fourteen million, two hundred forty-one thousand, thirty-three".