Base | Representation |
---|---|
bin | 1011000111011111100000… |
… | …0110000110000011010111 |
3 | 1121021112120212210022122102 |
4 | 2301313320012012003113 |
5 | 3100231402120214333 |
6 | 41555154333352315 |
7 | 2401051603201604 |
oct | 261677006060327 |
9 | 47245525708572 |
10 | 12223344304343 |
11 | 399298921a407 |
12 | 1454b7133869b |
13 | 6a886c20b7a3 |
14 | 3038821b56ab |
15 | 162e55a15ae8 |
hex | b1df81860d7 |
12223344304343 has 2 divisors, whose sum is σ = 12223344304344. Its totient is φ = 12223344304342.
The previous prime is 12223344304337. The next prime is 12223344304351. The reversal of 12223344304343 is 34340344332221.
12223344304343 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12223344304343 - 218 = 12223344042199 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12223344304297 and 12223344304306.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12223344304543) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6111672152171 + 6111672152172.
It is an arithmetic number, because the mean of its divisors is an integer number (6111672152172).
Almost surely, 212223344304343 is an apocalyptic number.
12223344304343 is a deficient number, since it is larger than the sum of its proper divisors (1).
12223344304343 is an equidigital number, since it uses as much as digits as its factorization.
12223344304343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 497664, while the sum is 38.
Adding to 12223344304343 its reverse (34340344332221), we get a palindrome (46563688636564).
The spelling of 12223344304343 in words is "twelve trillion, two hundred twenty-three billion, three hundred forty-four million, three hundred four thousand, three hundred forty-three".
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