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12223344304343 is a prime number
BaseRepresentation
bin1011000111011111100000…
…0110000110000011010111
31121021112120212210022122102
42301313320012012003113
53100231402120214333
641555154333352315
72401051603201604
oct261677006060327
947245525708572
1012223344304343
11399298921a407
121454b7133869b
136a886c20b7a3
143038821b56ab
15162e55a15ae8
hexb1df81860d7

12223344304343 has 2 divisors, whose sum is σ = 12223344304344. Its totient is φ = 12223344304342.

The previous prime is 12223344304337. The next prime is 12223344304351. The reversal of 12223344304343 is 34340344332221.

12223344304343 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 12223344304343 - 218 = 12223344042199 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12223344304297 and 12223344304306.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12223344304543) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6111672152171 + 6111672152172.

It is an arithmetic number, because the mean of its divisors is an integer number (6111672152172).

Almost surely, 212223344304343 is an apocalyptic number.

12223344304343 is a deficient number, since it is larger than the sum of its proper divisors (1).

12223344304343 is an equidigital number, since it uses as much as digits as its factorization.

12223344304343 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 497664, while the sum is 38.

Adding to 12223344304343 its reverse (34340344332221), we get a palindrome (46563688636564).

The spelling of 12223344304343 in words is "twelve trillion, two hundred twenty-three billion, three hundred forty-four million, three hundred four thousand, three hundred forty-three".