Base | Representation |
---|---|
bin | 10001110010011001010… |
… | …101000010010000100111 |
3 | 11022212002012021020120122 |
4 | 101302121111002100213 |
5 | 130011324320443031 |
6 | 2333311531352155 |
7 | 154211542156022 |
oct | 21623125022047 |
9 | 4285065236518 |
10 | 1222343140391 |
11 | 43143592217a |
12 | 178a942b265b |
13 | 8b360560839 |
14 | 43239aac1b9 |
15 | 21be14ea47b |
hex | 11c99542427 |
1222343140391 has 2 divisors, whose sum is σ = 1222343140392. Its totient is φ = 1222343140390.
The previous prime is 1222343140363. The next prime is 1222343140393. The reversal of 1222343140391 is 1930413432221.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1222343140391 is a prime.
Together with 1222343140393, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1222343140393) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 611171570195 + 611171570196.
It is an arithmetic number, because the mean of its divisors is an integer number (611171570196).
Almost surely, 21222343140391 is an apocalyptic number.
1222343140391 is a deficient number, since it is larger than the sum of its proper divisors (1).
1222343140391 is an equidigital number, since it uses as much as digits as its factorization.
1222343140391 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 31104, while the sum is 35.
The spelling of 1222343140391 in words is "one trillion, two hundred twenty-two billion, three hundred forty-three million, one hundred forty thousand, three hundred ninety-one".
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