Base | Representation |
---|---|
bin | 10001110010011001010… |
… | …101110000100011100111 |
3 | 11022212002012121212201001 |
4 | 101302121111300203213 |
5 | 130011324343030043 |
6 | 2333311535414131 |
7 | 154211543605624 |
oct | 21623125604347 |
9 | 4285065555631 |
10 | 1222343330023 |
11 | 431435a416a2 |
12 | 178a94384347 |
13 | 8b3605c8c4a |
14 | 43239b1b34b |
15 | 21be153674d |
hex | 11c995708e7 |
1222343330023 has 2 divisors, whose sum is σ = 1222343330024. Its totient is φ = 1222343330022.
The previous prime is 1222343330011. The next prime is 1222343330051. The reversal of 1222343330023 is 3200333432221.
It is an a-pointer prime, because the next prime (1222343330051) can be obtained adding 1222343330023 to its sum of digits (28).
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1222343330023 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1222343329973 and 1222343330000.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1222343330003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 611171665011 + 611171665012.
It is an arithmetic number, because the mean of its divisors is an integer number (611171665012).
Almost surely, 21222343330023 is an apocalyptic number.
1222343330023 is a deficient number, since it is larger than the sum of its proper divisors (1).
1222343330023 is an equidigital number, since it uses as much as digits as its factorization.
1222343330023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 28.
Adding to 1222343330023 its reverse (3200333432221), we get a palindrome (4422676762244).
The spelling of 1222343330023 in words is "one trillion, two hundred twenty-two billion, three hundred forty-three million, three hundred thirty thousand, twenty-three".
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