Base | Representation |
---|---|
bin | 1011000111100010000100… |
… | …1110101100000100011111 |
3 | 1121021121100222100222120022 |
4 | 2301320201032230010133 |
5 | 3100234310303014241 |
6 | 41555351025142355 |
7 | 2401104653126552 |
oct | 261704116540437 |
9 | 47247328328508 |
10 | 12224034423071 |
11 | 399320282a869 |
12 | 145512448a9bb |
13 | 6a894c19b373 |
14 | 303909ada699 |
15 | 162e963d554b |
hex | b1e213ac11f |
12224034423071 has 2 divisors, whose sum is σ = 12224034423072. Its totient is φ = 12224034423070.
The previous prime is 12224034423061. The next prime is 12224034423109. The reversal of 12224034423071 is 17032443042221.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (17032443042221) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12224034423071 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12224034423031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6112017211535 + 6112017211536.
It is an arithmetic number, because the mean of its divisors is an integer number (6112017211536).
Almost surely, 212224034423071 is an apocalyptic number.
12224034423071 is a deficient number, since it is larger than the sum of its proper divisors (1).
12224034423071 is an equidigital number, since it uses as much as digits as its factorization.
12224034423071 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 64512, while the sum is 35.
Adding to 12224034423071 its reverse (17032443042221), we get a palindrome (29256477465292).
The spelling of 12224034423071 in words is "twelve trillion, two hundred twenty-four billion, thirty-four million, four hundred twenty-three thousand, seventy-one".
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