Base | Representation |
---|---|
bin | 10001110011000100111… |
… | …010000100101100000001 |
3 | 11022220222011000110210022 |
4 | 101303010322010230001 |
5 | 130014324003114303 |
6 | 2333512250143225 |
7 | 154235630522054 |
oct | 21630472045401 |
9 | 4286864013708 |
10 | 1223074269953 |
11 | 4317805a3688 |
12 | 179059121b15 |
13 | 8b448b7c093 |
14 | 432a8c2aa9b |
15 | 21c357bb438 |
hex | 11cc4e84b01 |
1223074269953 has 2 divisors, whose sum is σ = 1223074269954. Its totient is φ = 1223074269952.
The previous prime is 1223074269899. The next prime is 1223074269959. The reversal of 1223074269953 is 3599624703221.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1182684525169 + 40389744784 = 1087513^2 + 200972^2 .
It is a cyclic number.
It is not a de Polignac number, because 1223074269953 - 210 = 1223074268929 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 1223074269895 and 1223074269904.
It is not a weakly prime, because it can be changed into another prime (1223074269959) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 611537134976 + 611537134977.
It is an arithmetic number, because the mean of its divisors is an integer number (611537134977).
Almost surely, 21223074269953 is an apocalyptic number.
It is an amenable number.
1223074269953 is a deficient number, since it is larger than the sum of its proper divisors (1).
1223074269953 is an equidigital number, since it uses as much as digits as its factorization.
1223074269953 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4898880, while the sum is 53.
The spelling of 1223074269953 in words is "one trillion, two hundred twenty-three billion, seventy-four million, two hundred sixty-nine thousand, nine hundred fifty-three".
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