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122311223251409 is a prime number
BaseRepresentation
bin11011110011110111001101…
…000000111001000111010001
3121001001211122110002011020202
4123303313031000321013101
5112012421341123021114
61112045000020144545
734522460063525303
oct3363671500710721
9531054573064222
10122311223251409
1135a76997973185
1211874899238155
135332b8ba528ba
14222bc75447973
15e218e027ecde
hex6f3dcd0391d1

122311223251409 has 2 divisors, whose sum is σ = 122311223251410. Its totient is φ = 122311223251408.

The previous prime is 122311223251339. The next prime is 122311223251411. The reversal of 122311223251409 is 904152322113221.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 110830951306384 + 11480271945025 = 10527628^2 + 3388255^2 .

It is a cyclic number.

It is not a de Polignac number, because 122311223251409 - 28 = 122311223251153 is a prime.

Together with 122311223251411, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (122311223251439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61155611625704 + 61155611625705.

It is an arithmetic number, because the mean of its divisors is an integer number (61155611625705).

Almost surely, 2122311223251409 is an apocalyptic number.

It is an amenable number.

122311223251409 is a deficient number, since it is larger than the sum of its proper divisors (1).

122311223251409 is an equidigital number, since it uses as much as digits as its factorization.

122311223251409 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 51840, while the sum is 38.

The spelling of 122311223251409 in words is "one hundred twenty-two trillion, three hundred eleven billion, two hundred twenty-three million, two hundred fifty-one thousand, four hundred nine".