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12231244400281 is a prime number
BaseRepresentation
bin1011000111111100111011…
…1110100100011010011001
31121022021222110012202221021
42301333032332210122121
53100344042031302111
642002542304042441
72401451431666354
oct261771676443231
947267873182837
1012231244400281
113996272661415
1214565b7003421
136a952ab4297a
14303dd14b529b
15163269379d71
hexb1fcefa4699

12231244400281 has 2 divisors, whose sum is σ = 12231244400282. Its totient is φ = 12231244400280.

The previous prime is 12231244400279. The next prime is 12231244400383. The reversal of 12231244400281 is 18200444213221.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11666214061056 + 565030339225 = 3415584^2 + 751685^2 .

It is an emirp because it is prime and its reverse (18200444213221) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12231244400281 - 21 = 12231244400279 is a prime.

It is a super-2 number, since 2×122312444002812 (a number of 27 digits) contains 22 as substring.

Together with 12231244400279, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (12231244430281) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6115622200140 + 6115622200141.

It is an arithmetic number, because the mean of its divisors is an integer number (6115622200141).

Almost surely, 212231244400281 is an apocalyptic number.

It is an amenable number.

12231244400281 is a deficient number, since it is larger than the sum of its proper divisors (1).

12231244400281 is an equidigital number, since it uses as much as digits as its factorization.

12231244400281 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24576, while the sum is 34.

The spelling of 12231244400281 in words is "twelve trillion, two hundred thirty-one billion, two hundred forty-four million, four hundred thousand, two hundred eighty-one".