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122322021312089 is a prime number
BaseRepresentation
bin11011110100000001010000…
…101000001110011001011001
3121001002212111222112110211002
4123310001100220032121121
5112013110444423441324
61112053543312114345
734523321501525624
oct3364012050163131
9531085458473732
10122322021312089
1135a80529113a75
12118769b15359b5
135333bbcb94311
14222c5bb58cdbb
15e21d232303ae
hex6f4050a0e659

122322021312089 has 2 divisors, whose sum is σ = 122322021312090. Its totient is φ = 122322021312088.

The previous prime is 122322021312079. The next prime is 122322021312229. The reversal of 122322021312089 is 980213120223221.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 77369756736064 + 44952264576025 = 8796008^2 + 6704645^2 .

It is an emirp because it is prime and its reverse (980213120223221) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 122322021312089 - 240 = 121222509684313 is a prime.

It is a super-2 number, since 2×1223220213120892 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (122322021312059) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61161010656044 + 61161010656045.

It is an arithmetic number, because the mean of its divisors is an integer number (61161010656045).

Almost surely, 2122322021312089 is an apocalyptic number.

It is an amenable number.

122322021312089 is a deficient number, since it is larger than the sum of its proper divisors (1).

122322021312089 is an equidigital number, since it uses as much as digits as its factorization.

122322021312089 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 41472, while the sum is 38.

The spelling of 122322021312089 in words is "one hundred twenty-two trillion, three hundred twenty-two billion, twenty-one million, three hundred twelve thousand, eighty-nine".