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122330113035047 is a prime number
BaseRepresentation
bin11011110100001000110010…
…111011101100101100100111
3121001010122101220112120221222
4123310020302323230230213
5112013224032414110142
61112101402245530555
734524026145165641
oct3364106273545447
9531118356476858
10122330113035047
1135a83a0073a215
121187848b413a5b
1353348ac410678
14222cb480d1891
15e221487e7bd2
hex6f4232eecb27

122330113035047 has 2 divisors, whose sum is σ = 122330113035048. Its totient is φ = 122330113035046.

The previous prime is 122330113035007. The next prime is 122330113035049. The reversal of 122330113035047 is 740530311033221.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 122330113035047 - 28 = 122330113034791 is a prime.

Together with 122330113035049, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 122330113034998 and 122330113035016.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (122330113035049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61165056517523 + 61165056517524.

It is an arithmetic number, because the mean of its divisors is an integer number (61165056517524).

Almost surely, 2122330113035047 is an apocalyptic number.

122330113035047 is a deficient number, since it is larger than the sum of its proper divisors (1).

122330113035047 is an equidigital number, since it uses as much as digits as its factorization.

122330113035047 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 45360, while the sum is 35.

Adding to 122330113035047 its reverse (740530311033221), we get a palindrome (862860424068268).

The spelling of 122330113035047 in words is "one hundred twenty-two trillion, three hundred thirty billion, one hundred thirteen million, thirty-five thousand, forty-seven".