Base | Representation |
---|---|
bin | 1011001000000011100011… |
… | …1000101011101101011111 |
3 | 1121022110120021122200211111 |
4 | 2302000320320223231133 |
5 | 3100411211414222312 |
6 | 42003434500002451 |
7 | 2401543445622463 |
oct | 262007070535537 |
9 | 47273507580744 |
10 | 12233021242207 |
11 | 3996aa4639017 |
12 | 1456a12090427 |
13 | 6a9751cb501c |
14 | 30411d4804a3 |
15 | 16332035b8a7 |
hex | b2038e2bb5f |
12233021242207 has 2 divisors, whose sum is σ = 12233021242208. Its totient is φ = 12233021242206.
The previous prime is 12233021242151. The next prime is 12233021242259. The reversal of 12233021242207 is 70224212033221.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12233021242207 - 215 = 12233021209439 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12233021242307) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6116510621103 + 6116510621104.
It is an arithmetic number, because the mean of its divisors is an integer number (6116510621104).
Almost surely, 212233021242207 is an apocalyptic number.
12233021242207 is a deficient number, since it is larger than the sum of its proper divisors (1).
12233021242207 is an equidigital number, since it uses as much as digits as its factorization.
12233021242207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16128, while the sum is 31.
Adding to 12233021242207 its reverse (70224212033221), we get a palindrome (82457233275428).
The spelling of 12233021242207 in words is "twelve trillion, two hundred thirty-three billion, twenty-one million, two hundred forty-two thousand, two hundred seven".
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