Search a number
-
+
122331302017 is a prime number
BaseRepresentation
bin111000111101110000…
…0111000100010000001
3102200202110221000122121
41301323200320202001
54001013303131032
6132110452204241
711560324624201
oct1617340704201
9380673830577
10122331302017
1147975915901
121b860609681
13b6c719c012
145cc6c02401
1532ae9aba97
hex1c7b838881

122331302017 has 2 divisors, whose sum is σ = 122331302018. Its totient is φ = 122331302016.

The previous prime is 122331301993. The next prime is 122331302021. The reversal of 122331302017 is 710203133221.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 117922873201 + 4408428816 = 343399^2 + 66396^2 .

It is a cyclic number.

It is not a de Polignac number, because 122331302017 - 27 = 122331301889 is a prime.

It is a super-3 number, since 3×1223313020173 (a number of 34 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 122331301982 and 122331302000.

It is not a weakly prime, because it can be changed into another prime (122331302087) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61165651008 + 61165651009.

It is an arithmetic number, because the mean of its divisors is an integer number (61165651009).

Almost surely, 2122331302017 is an apocalyptic number.

It is an amenable number.

122331302017 is a deficient number, since it is larger than the sum of its proper divisors (1).

122331302017 is an equidigital number, since it uses as much as digits as its factorization.

122331302017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1512, while the sum is 25.

Adding to 122331302017 its reverse (710203133221), we get a palindrome (832534435238).

The spelling of 122331302017 in words is "one hundred twenty-two billion, three hundred thirty-one million, three hundred two thousand, seventeen".