Base | Representation |
---|---|
bin | 111001000000011011… |
… | …1100001000001101101 |
3 | 102200222201221022022112 |
4 | 1302000313201001231 |
5 | 4001204301334013 |
6 | 132123421253405 |
7 | 11562465234413 |
oct | 1620067410155 |
9 | 380881838275 |
10 | 122421121133 |
11 | 47a11593283 |
12 | 1b886704265 |
13 | b70c98981c |
14 | 5cd4b032b3 |
15 | 32b77eeba8 |
hex | 1c80de106d |
122421121133 has 2 divisors, whose sum is σ = 122421121134. Its totient is φ = 122421121132.
The previous prime is 122421121129. The next prime is 122421121211. The reversal of 122421121133 is 331121124221.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 81697073929 + 40724047204 = 285827^2 + 201802^2 .
It is a cyclic number.
It is not a de Polignac number, because 122421121133 - 22 = 122421121129 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 122421121099 and 122421121108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (122421126133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61210560566 + 61210560567.
It is an arithmetic number, because the mean of its divisors is an integer number (61210560567).
Almost surely, 2122421121133 is an apocalyptic number.
It is an amenable number.
122421121133 is a deficient number, since it is larger than the sum of its proper divisors (1).
122421121133 is an equidigital number, since it uses as much as digits as its factorization.
122421121133 is an evil number, because the sum of its binary digits is even.
The product of its digits is 576, while the sum is 23.
Adding to 122421121133 its reverse (331121124221), we get a palindrome (453542245354).
The spelling of 122421121133 in words is "one hundred twenty-two billion, four hundred twenty-one million, one hundred twenty-one thousand, one hundred thirty-three".
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