Base | Representation |
---|---|
bin | 10110110011011000… |
… | …00100110010100111 |
3 | 1011121011202101001102 |
4 | 23121230010302213 |
5 | 200032442110143 |
6 | 5342435350315 |
7 | 612241340105 |
oct | 133154046247 |
9 | 34534671042 |
10 | 12242144423 |
11 | 521240a333 |
12 | 2457a5239b |
13 | 1201386752 |
14 | 841c50c75 |
15 | 4b9b520b8 |
hex | 2d9b04ca7 |
12242144423 has 2 divisors, whose sum is σ = 12242144424. Its totient is φ = 12242144422.
The previous prime is 12242144401. The next prime is 12242144441. The reversal of 12242144423 is 32444124221.
It is a happy number.
12242144423 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (32444124221) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12242144423 - 210 = 12242143399 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12242144443) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6121072211 + 6121072212.
It is an arithmetic number, because the mean of its divisors is an integer number (6121072212).
Almost surely, 212242144423 is an apocalyptic number.
12242144423 is a deficient number, since it is larger than the sum of its proper divisors (1).
12242144423 is an equidigital number, since it uses as much as digits as its factorization.
12242144423 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 12288, while the sum is 29.
Adding to 12242144423 its reverse (32444124221), we get a palindrome (44686268644).
The spelling of 12242144423 in words is "twelve billion, two hundred forty-two million, one hundred forty-four thousand, four hundred twenty-three".
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