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1225443433 is a prime number
BaseRepresentation
bin100100100001010…
…1100100001101001
310011101212222100211
41021002230201221
510002203142213
6321333301121
742240045244
oct11102544151
93141788324
101225443433
11579804875
122a24947a1
13166b62476
14b8a7425b
15728b453d
hex490ac869

1225443433 has 2 divisors, whose sum is σ = 1225443434. Its totient is φ = 1225443432.

The previous prime is 1225443431. The next prime is 1225443449. The reversal of 1225443433 is 3343445221.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1188318784 + 37124649 = 34472^2 + 6093^2 .

It is an emirp because it is prime and its reverse (3343445221) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1225443433 - 21 = 1225443431 is a prime.

Together with 1225443431, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 1225443395 and 1225443404.

It is not a weakly prime, because it can be changed into another prime (1225443431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 612721716 + 612721717.

It is an arithmetic number, because the mean of its divisors is an integer number (612721717).

Almost surely, 21225443433 is an apocalyptic number.

It is an amenable number.

1225443433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1225443433 is an equidigital number, since it uses as much as digits as its factorization.

1225443433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 34560, while the sum is 31.

The square root of 1225443433 is about 35006.3341839730. The cubic root of 1225443433 is about 1070.1165718630.

Adding to 1225443433 its reverse (3343445221), we get a palindrome (4568888654).

The spelling of 1225443433 in words is "one billion, two hundred twenty-five million, four hundred forty-three thousand, four hundred thirty-three".