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12255431311301 is a prime number
BaseRepresentation
bin1011001001010111000010…
…1000010011111111000101
31121101121102002011011100112
42302111300220103333011
53101243110403430201
642022022321322405
72403266004231053
oct262256050237705
947347362134315
1012255431311301
1139a5554527682
12145b227196405
136ab8b3a92739
143052478871d3
15163bd298c0bb
hexb2570a13fc5

12255431311301 has 2 divisors, whose sum is σ = 12255431311302. Its totient is φ = 12255431311300.

The previous prime is 12255431311219. The next prime is 12255431311309. The reversal of 12255431311301 is 10311313455221.

12255431311301 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11658134188801 + 597297122500 = 3414401^2 + 772850^2 .

It is a cyclic number.

It is not a de Polignac number, because 12255431311301 - 222 = 12255427116997 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12255431311309) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6127715655650 + 6127715655651.

It is an arithmetic number, because the mean of its divisors is an integer number (6127715655651).

Almost surely, 212255431311301 is an apocalyptic number.

It is an amenable number.

12255431311301 is a deficient number, since it is larger than the sum of its proper divisors (1).

12255431311301 is an equidigital number, since it uses as much as digits as its factorization.

12255431311301 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10800, while the sum is 32.

Adding to 12255431311301 its reverse (10311313455221), we get a palindrome (22566744766522).

The spelling of 12255431311301 in words is "twelve trillion, two hundred fifty-five billion, four hundred thirty-one million, three hundred eleven thousand, three hundred one".