Base | Representation |
---|---|
bin | 1011001011111101000111… |
… | …1111011000000010100110 |
3 | 1121112212111011010202020121 |
4 | 2302333101333120002212 |
5 | 3103010412142421014 |
6 | 42054314300152154 |
7 | 2406434552344150 |
oct | 262772177300246 |
9 | 47485434122217 |
10 | 12300014420134 |
11 | 3a12452530171 |
12 | 14679a9b3865a |
13 | 6b2b6a4c9bcc |
14 | 3074769d5ad0 |
15 | 164e419cc124 |
hex | b2fd1fd80a6 |
12300014420134 has 64 divisors (see below), whose sum is σ = 22827563016192. Its totient is φ = 4854818707200.
The previous prime is 12300014420129. The next prime is 12300014420147. The reversal of 12300014420134 is 43102441000321.
It is a junction number, because it is equal to n+sod(n) for n = 12300014420099 and 12300014420108.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1161007 + ... + 5093914.
It is an arithmetic number, because the mean of its divisors is an integer number (356680672128).
Almost surely, 212300014420134 is an apocalyptic number.
12300014420134 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
12300014420134 is a deficient number, since it is larger than the sum of its proper divisors (10527548596058).
12300014420134 is a wasteful number, since it uses less digits than its factorization.
12300014420134 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6255181.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 12300014420134 its reverse (43102441000321), we get a palindrome (55402455420455).
The spelling of 12300014420134 in words is "twelve trillion, three hundred billion, fourteen million, four hundred twenty thousand, one hundred thirty-four".
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