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123002311114349 is a prime number
BaseRepresentation
bin11011111101111010110101…
…000011110111111001101101
3121010111220110112211002021022
4123331322311003313321231
5112110232213121124344
61113334252011343525
734623423635453042
oct3375726503677155
9533456415732238
10123002311114349
1136212a94a62347
1211966809151ba5
1353830b69c3854
1422534b4c891c9
15e3488bc140ee
hex6fdeb50f7e6d

123002311114349 has 2 divisors, whose sum is σ = 123002311114350. Its totient is φ = 123002311114348.

The previous prime is 123002311114279. The next prime is 123002311114351. The reversal of 123002311114349 is 943411113200321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 96509600644900 + 26492710469449 = 9823930^2 + 5147107^2 .

It is a cyclic number.

It is not a de Polignac number, because 123002311114349 - 28 = 123002311114093 is a prime.

It is a super-2 number, since 2×1230023111143492 (a number of 29 digits) contains 22 as substring.

Together with 123002311114351, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (123002311114369) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61501155557174 + 61501155557175.

It is an arithmetic number, because the mean of its divisors is an integer number (61501155557175).

Almost surely, 2123002311114349 is an apocalyptic number.

It is an amenable number.

123002311114349 is a deficient number, since it is larger than the sum of its proper divisors (1).

123002311114349 is an equidigital number, since it uses as much as digits as its factorization.

123002311114349 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15552, while the sum is 35.

The spelling of 123002311114349 in words is "one hundred twenty-three trillion, two billion, three hundred eleven million, one hundred fourteen thousand, three hundred forty-nine".