Base | Representation |
---|---|
bin | 1011001011111111000001… |
… | …0000100001100011000011 |
3 | 1121112220210112200021011121 |
4 | 2302333300100201203003 |
5 | 3103012432142411003 |
6 | 42054440520253111 |
7 | 2406453256565215 |
oct | 262776020414303 |
9 | 47486715607147 |
10 | 12300522232003 |
11 | 3a126931427a5 |
12 | 1467b10011197 |
13 | 6b2c1b7888c5 |
14 | 3074c42225b5 |
15 | 164e71389cbd |
hex | b2ff04218c3 |
12300522232003 has 2 divisors, whose sum is σ = 12300522232004. Its totient is φ = 12300522232002.
The previous prime is 12300522232001. The next prime is 12300522232109. The reversal of 12300522232003 is 30023222500321.
It is a weak prime.
It is an emirp because it is prime and its reverse (30023222500321) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12300522232003 - 21 = 12300522232001 is a prime.
Together with 12300522232001, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (12300522232001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6150261116001 + 6150261116002.
It is an arithmetic number, because the mean of its divisors is an integer number (6150261116002).
Almost surely, 212300522232003 is an apocalyptic number.
12300522232003 is a deficient number, since it is larger than the sum of its proper divisors (1).
12300522232003 is an equidigital number, since it uses as much as digits as its factorization.
12300522232003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4320, while the sum is 25.
Adding to 12300522232003 its reverse (30023222500321), we get a palindrome (42323744732324).
The spelling of 12300522232003 in words is "twelve trillion, three hundred billion, five hundred twenty-two million, two hundred thirty-two thousand, three".
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