12301041442127 has 2 divisors, whose sum is σ = 12301041442128. Its totient is φ = 12301041442126.

The previous prime is 12301041442121. The next prime is 12301041442153. The reversal of 12301041442127 is 72124414010321.

12301041442127 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 12301041442127 - 2¹⁸ = 12301041179983 is a prime.

It is a super-3 number, since 3×12301041442127³ (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12301041442093 and 12301041442102.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12301041442121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6150520721063 + 6150520721064.

It is an arithmetic number, because the mean of its divisors is an integer number (6150520721064).

Almost surely, 2^{12301041442127} is an apocalyptic number.

12301041442127 is a deficient number, since it is larger than the sum of its proper divisors (1).

12301041442127 is an equidigital number, since it uses as much as digits as its factorization.

12301041442127 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10752, while the sum is 32.

Adding to 12301041442127 its reverse (72124414010321), we get a palindrome (84425455452448).

The spelling of 12301041442127 in words is "twelve trillion, three hundred one billion, forty-one million, four hundred forty-two thousand, one hundred twenty-seven".