Base | Representation |
---|---|
bin | 11011111110000011000010… |
… | …101101101001001000111010 |
3 | 121010112202020011022002110210 |
4 | 123332003002231221020322 |
5 | 112110403243301233310 |
6 | 1113342311045051550 |
7 | 34624155322562211 |
oct | 3376030255511072 |
9 | 533482204262423 |
10 | 123011130102330 |
11 | 3621680005a568 |
12 | 1196846a6b6bb6 |
13 | 5383b90b07432 |
14 | 2253ab0222078 |
15 | e34c06087820 |
hex | 6fe0c2b6923a |
123011130102330 has 16 divisors (see below), whose sum is σ = 295226712245664. Its totient is φ = 32802968027280.
The previous prime is 123011130102307. The next prime is 123011130102383. The reversal of 123011130102330 is 33201031110321.
It is a happy number.
It is a junction number, because it is equal to n+sod(n) for n = 123011130102297 and 123011130102306.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2050185501676 + ... + 2050185501735.
It is an arithmetic number, because the mean of its divisors is an integer number (18451669515354).
Almost surely, 2123011130102330 is an apocalyptic number.
123011130102330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
123011130102330 is an abundant number, since it is smaller than the sum of its proper divisors (172215582143334).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
123011130102330 is a wasteful number, since it uses less digits than its factorization.
123011130102330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4100371003421.
The product of its (nonzero) digits is 324, while the sum is 21.
Adding to 123011130102330 its reverse (33201031110321), we get a palindrome (156212161212651).
The spelling of 123011130102330 in words is "one hundred twenty-three trillion, eleven billion, one hundred thirty million, one hundred two thousand, three hundred thirty".
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