Base | Representation |
---|---|
bin | 10001111001101110011… |
… | …010010010010011010111 |
3 | 11100121101122212010010022 |
4 | 101321232122102103113 |
5 | 130123434013444002 |
6 | 2341052502415355 |
7 | 154610553141623 |
oct | 21715632222327 |
9 | 4317348763108 |
10 | 1230213031127 |
11 | 434804203603 |
12 | 17a50ba3155b |
13 | 8c015b4a512 |
14 | 43784d88183 |
15 | 22002394ba2 |
hex | 11e6e6924d7 |
1230213031127 has 2 divisors, whose sum is σ = 1230213031128. Its totient is φ = 1230213031126.
The previous prime is 1230213031063. The next prime is 1230213031129. The reversal of 1230213031127 is 7211303120321.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1230213031127 - 26 = 1230213031063 is a prime.
Together with 1230213031129, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 1230213031096 and 1230213031105.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1230213031129) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 615106515563 + 615106515564.
It is an arithmetic number, because the mean of its divisors is an integer number (615106515564).
Almost surely, 21230213031127 is an apocalyptic number.
1230213031127 is a deficient number, since it is larger than the sum of its proper divisors (1).
1230213031127 is an equidigital number, since it uses as much as digits as its factorization.
1230213031127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 26.
Adding to 1230213031127 its reverse (7211303120321), we get a palindrome (8441516151448).
The spelling of 1230213031127 in words is "one trillion, two hundred thirty billion, two hundred thirteen million, thirty-one thousand, one hundred twenty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •