Base | Representation |
---|---|
bin | 11011111110010100101111… |
… | …010001001010011010000101 |
3 | 121010121120021101020222201021 |
4 | 123332110233101022122011 |
5 | 112111211202043102044 |
6 | 1113355132333031141 |
7 | 34625430225461044 |
oct | 3376245721123205 |
9 | 533546241228637 |
10 | 123030131222149 |
11 | 36223870760078 |
12 | 119700920254b1 |
13 | 53858cb5777b8 |
14 | 22549939ac55b |
15 | e35469293e84 |
hex | 6fe52f44a685 |
123030131222149 has 2 divisors, whose sum is σ = 123030131222150. Its totient is φ = 123030131222148.
The previous prime is 123030131222083. The next prime is 123030131222191. The reversal of 123030131222149 is 941222131030321.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 89348149332225 + 33681981889924 = 9452415^2 + 5803618^2 .
It is a cyclic number.
It is not a de Polignac number, because 123030131222149 - 29 = 123030131221637 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (123030131222249) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61515065611074 + 61515065611075.
It is an arithmetic number, because the mean of its divisors is an integer number (61515065611075).
Almost surely, 2123030131222149 is an apocalyptic number.
It is an amenable number.
123030131222149 is a deficient number, since it is larger than the sum of its proper divisors (1).
123030131222149 is an equidigital number, since it uses as much as digits as its factorization.
123030131222149 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15552, while the sum is 34.
The spelling of 123030131222149 in words is "one hundred twenty-three trillion, thirty billion, one hundred thirty-one million, two hundred twenty-two thousand, one hundred forty-nine".
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