Base | Representation |
---|---|
bin | 10110111010101000… |
… | …11010011010100111 |
3 | 1011202102100201100121 |
4 | 23131110122122213 |
5 | 200144040103112 |
6 | 5352453022411 |
7 | 613611126424 |
oct | 133524323247 |
9 | 34672321317 |
10 | 12303050407 |
11 | 524382995a |
12 | 2474324a07 |
13 | 1210b8cbab |
14 | 849d86d4b |
15 | 4c0183407 |
hex | 2dd51a6a7 |
12303050407 has 2 divisors, whose sum is σ = 12303050408. Its totient is φ = 12303050406.
The previous prime is 12303050381. The next prime is 12303050413. The reversal of 12303050407 is 70405030321.
It is a strong prime.
It is an emirp because it is prime and its reverse (70405030321) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12303050407 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12303050437) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6151525203 + 6151525204.
It is an arithmetic number, because the mean of its divisors is an integer number (6151525204).
Almost surely, 212303050407 is an apocalyptic number.
12303050407 is a deficient number, since it is larger than the sum of its proper divisors (1).
12303050407 is an equidigital number, since it uses as much as digits as its factorization.
12303050407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2520, while the sum is 25.
Adding to 12303050407 its reverse (70405030321), we get a palindrome (82708080728).
The spelling of 12303050407 in words is "twelve billion, three hundred three million, fifty thousand, four hundred seven".
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