Base | Representation |
---|---|
bin | 111001010010100111… |
… | …0011100001000110101 |
3 | 102202120020201222000002 |
4 | 1302211032130020311 |
5 | 4003431431011242 |
6 | 132304131401045 |
7 | 11613553116242 |
oct | 1624516341065 |
9 | 382506658002 |
10 | 123031110197 |
11 | 481a4944076 |
12 | 1ba16a53185 |
13 | b7a9171cb8 |
14 | 5d51b2a5c9 |
15 | 3301142432 |
hex | 1ca539c235 |
123031110197 has 2 divisors, whose sum is σ = 123031110198. Its totient is φ = 123031110196.
The previous prime is 123031110119. The next prime is 123031110199. The reversal of 123031110197 is 791011130321.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 65107135921 + 57923974276 = 255161^2 + 240674^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-123031110197 is a prime.
Together with 123031110199, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (123031110199) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61515555098 + 61515555099.
It is an arithmetic number, because the mean of its divisors is an integer number (61515555099).
Almost surely, 2123031110197 is an apocalyptic number.
It is an amenable number.
123031110197 is a deficient number, since it is larger than the sum of its proper divisors (1).
123031110197 is an equidigital number, since it uses as much as digits as its factorization.
123031110197 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1134, while the sum is 29.
The spelling of 123031110197 in words is "one hundred twenty-three billion, thirty-one million, one hundred ten thousand, one hundred ninety-seven".
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