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1230440110421 is a prime number
BaseRepresentation
bin10001111001111011111…
…100100001100101010101
311100121222111010221100112
4101321323330201211111
5130124420132013141
62341131213452405
7154616311241444
oct21717374414525
94317874127315
101230440110421
11434910401645
1217a573aa1105
138c050bc6272
14437a71b8d5b
152201729c7eb
hex11e7bf21955

1230440110421 has 2 divisors, whose sum is σ = 1230440110422. Its totient is φ = 1230440110420.

The previous prime is 1230440110307. The next prime is 1230440110423. The reversal of 1230440110421 is 1240110440321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 885272110321 + 345168000100 = 940889^2 + 587510^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1230440110421 is a prime.

Together with 1230440110423, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1230440110423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 615220055210 + 615220055211.

It is an arithmetic number, because the mean of its divisors is an integer number (615220055211).

Almost surely, 21230440110421 is an apocalyptic number.

It is an amenable number.

1230440110421 is a deficient number, since it is larger than the sum of its proper divisors (1).

1230440110421 is an equidigital number, since it uses as much as digits as its factorization.

1230440110421 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 1230440110421 its reverse (1240110440321), we get a palindrome (2470550550742).

The spelling of 1230440110421 in words is "one trillion, two hundred thirty billion, four hundred forty million, one hundred ten thousand, four hundred twenty-one".