Base | Representation |
---|---|
bin | 11011111110100001110001… |
… | …000100011111111000110011 |
3 | 121010122220101021210122010021 |
4 | 123332201301010133320303 |
5 | 112111423324221203103 |
6 | 1113405404411144311 |
7 | 34626434000125465 |
oct | 3376416104377063 |
9 | 533586337718107 |
10 | 123044120100403 |
11 | 3622979a052387 |
12 | 11972936a45097 |
13 | 538701a791358 |
14 | 225551d7cc135 |
15 | e359d742bbbd |
hex | 6fe87111fe33 |
123044120100403 has 2 divisors, whose sum is σ = 123044120100404. Its totient is φ = 123044120100402.
The previous prime is 123044120100397. The next prime is 123044120100409. The reversal of 123044120100403 is 304001021440321.
It is a balanced prime because it is at equal distance from previous prime (123044120100397) and next prime (123044120100409).
It is a cyclic number.
It is not a de Polignac number, because 123044120100403 - 29 = 123044120099891 is a prime.
It is not a weakly prime, because it can be changed into another prime (123044120100409) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61522060050201 + 61522060050202.
It is an arithmetic number, because the mean of its divisors is an integer number (61522060050202).
Almost surely, 2123044120100403 is an apocalyptic number.
123044120100403 is a deficient number, since it is larger than the sum of its proper divisors (1).
123044120100403 is an equidigital number, since it uses as much as digits as its factorization.
123044120100403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 123044120100403 its reverse (304001021440321), we get a palindrome (427045141540724).
The spelling of 123044120100403 in words is "one hundred twenty-three trillion, forty-four billion, one hundred twenty million, one hundred thousand, four hundred three".
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