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12304450445471 is a prime number
BaseRepresentation
bin1011001100001101101001…
…1001011110000010011111
31121120021221022022012000022
42303003122121132002133
53103044003303223341
642100330403422355
72406652516054502
oct263033231360237
947507838265008
1012304450445471
113a14319555708
1214688276849bb
136b33c6564582
14307777c0b139
1516510117ee4b
hexb30da65e09f

12304450445471 has 2 divisors, whose sum is σ = 12304450445472. Its totient is φ = 12304450445470.

The previous prime is 12304450445347. The next prime is 12304450445473. The reversal of 12304450445471 is 17454405440321.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12304450445471 - 226 = 12304383336607 is a prime.

It is a super-3 number, since 3×123044504454713 (a number of 40 digits) contains 333 as substring.

Together with 12304450445473, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12304450445473) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6152225222735 + 6152225222736.

It is an arithmetic number, because the mean of its divisors is an integer number (6152225222736).

Almost surely, 212304450445471 is an apocalyptic number.

12304450445471 is a deficient number, since it is larger than the sum of its proper divisors (1).

12304450445471 is an equidigital number, since it uses as much as digits as its factorization.

12304450445471 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1075200, while the sum is 44.

Adding to 12304450445471 its reverse (17454405440321), we get a palindrome (29758855885792).

The spelling of 12304450445471 in words is "twelve trillion, three hundred four billion, four hundred fifty million, four hundred forty-five thousand, four hundred seventy-one".