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123050115001421 is a prime number
BaseRepresentation
bin11011111110100111010110…
…011001001110110001001101
3121010200110212002021011022022
4123332213112121032301031
5112112023113420021141
61113412235322455525
734630035363006146
oct3376472631166115
9533613762234268
10123050115001421
1136231296010233
1211973b2a6645a5
13538776479326a
14225592ba70acd
15e35c388a8b4b
hex6fe9d664ec4d

123050115001421 has 2 divisors, whose sum is σ = 123050115001422. Its totient is φ = 123050115001420.

The previous prime is 123050115001369. The next prime is 123050115001427. The reversal of 123050115001421 is 124100511050321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 110845922098921 + 12204192902500 = 10528339^2 + 3493450^2 .

It is a cyclic number.

It is not a de Polignac number, because 123050115001421 - 214 = 123050114985037 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (123050115001427) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61525057500710 + 61525057500711.

It is an arithmetic number, because the mean of its divisors is an integer number (61525057500711).

Almost surely, 2123050115001421 is an apocalyptic number.

It is an amenable number.

123050115001421 is a deficient number, since it is larger than the sum of its proper divisors (1).

123050115001421 is an equidigital number, since it uses as much as digits as its factorization.

123050115001421 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1200, while the sum is 26.

Adding to 123050115001421 its reverse (124100511050321), we get a palindrome (247150626051742).

The spelling of 123050115001421 in words is "one hundred twenty-three trillion, fifty billion, one hundred fifteen million, one thousand, four hundred twenty-one".