123050115001427 has 2 divisors, whose sum is σ = 123050115001428. Its totient is φ = 123050115001426.

The previous prime is 123050115001421. The next prime is 123050115001433. The reversal of 123050115001427 is 724100511050321.

It is a balanced prime because it is at equal distance from previous prime (123050115001421) and next prime (123050115001433).

It is a cyclic number.

It is not a de Polignac number, because 123050115001427 - 2⁸ = 123050115001171 is a prime.

It is a super-3 number, since 3×123050115001427³ (a number of 43 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 123050115001393 and 123050115001402.

It is not a weakly prime, because it can be changed into another prime (123050115001421) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61525057500713 + 61525057500714.

It is an arithmetic number, because the mean of its divisors is an integer number (61525057500714).

Almost surely, 2^{123050115001427} is an apocalyptic number.

123050115001427 is a deficient number, since it is larger than the sum of its proper divisors (1).

123050115001427 is an equidigital number, since it uses as much as digits as its factorization.

123050115001427 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8400, while the sum is 32.

Adding to 123050115001427 its reverse (724100511050321), we get a palindrome (847150626051748).

The spelling of 123050115001427 in words is "one hundred twenty-three trillion, fifty billion, one hundred fifteen million, one thousand, four hundred twenty-seven".