Base | Representation |
---|---|
bin | 1011001100100010011111… |
… | …0011110000101010000111 |
3 | 1121120211101010211211122012 |
4 | 2303020213303300222013 |
5 | 3103141432300303112 |
6 | 42103053424124435 |
7 | 2410241240552243 |
oct | 263104763605207 |
9 | 47524333754565 |
10 | 12310044150407 |
11 | 3a1672a000a53 |
12 | 1469928a6671b |
13 | 6b3aa83c6653 |
14 | 307b48a97423 |
15 | 16532c2ae022 |
hex | b3227cf0a87 |
12310044150407 has 2 divisors, whose sum is σ = 12310044150408. Its totient is φ = 12310044150406.
The previous prime is 12310044150379. The next prime is 12310044150473. The reversal of 12310044150407 is 70405144001321.
12310044150407 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (70405144001321) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12310044150407 - 26 = 12310044150343 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12310044150497) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6155022075203 + 6155022075204.
It is an arithmetic number, because the mean of its divisors is an integer number (6155022075204).
Almost surely, 212310044150407 is an apocalyptic number.
12310044150407 is a deficient number, since it is larger than the sum of its proper divisors (1).
12310044150407 is an equidigital number, since it uses as much as digits as its factorization.
12310044150407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13440, while the sum is 32.
Adding to 12310044150407 its reverse (70405144001321), we get a palindrome (82715188151728).
The spelling of 12310044150407 in words is "twelve trillion, three hundred ten billion, forty-four million, one hundred fifty thousand, four hundred seven".
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