Base | Representation |
---|---|
bin | 10110111011100101… |
… | …11010111101101001 |
3 | 1011202222102001001021 |
4 | 23131302322331221 |
5 | 200203112014131 |
6 | 5353340252441 |
7 | 614036116225 |
oct | 133562727551 |
9 | 34688361037 |
10 | 12311048041 |
11 | 52482a1676 |
12 | 2476b41121 |
13 | 1212730216 |
14 | 84b069785 |
15 | 4c0c12e11 |
hex | 2ddcbaf69 |
12311048041 has 2 divisors, whose sum is σ = 12311048042. Its totient is φ = 12311048040.
The previous prime is 12311048039. The next prime is 12311048047. The reversal of 12311048041 is 14084011321.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10572158041 + 1738890000 = 102821^2 + 41700^2 .
It is a cyclic number.
It is not a de Polignac number, because 12311048041 - 21 = 12311048039 is a prime.
Together with 12311048039, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 12311047997 and 12311048015.
It is not a weakly prime, because it can be changed into another prime (12311048047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6155524020 + 6155524021.
It is an arithmetic number, because the mean of its divisors is an integer number (6155524021).
Almost surely, 212311048041 is an apocalyptic number.
It is an amenable number.
12311048041 is a deficient number, since it is larger than the sum of its proper divisors (1).
12311048041 is an equidigital number, since it uses as much as digits as its factorization.
12311048041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 768, while the sum is 25.
Adding to 12311048041 its reverse (14084011321), we get a palindrome (26395059362).
The spelling of 12311048041 in words is "twelve billion, three hundred eleven million, forty-eight thousand, forty-one".
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