Base | Representation |
---|---|
bin | 1011001100100110110111… |
… | …1110010001111001001100 |
3 | 1121120221102011212220021110 |
4 | 2303021231332101321030 |
5 | 3103201340124004400 |
6 | 42103410314532020 |
7 | 2410312353353403 |
oct | 263115576217114 |
9 | 47527364786243 |
10 | 12311221313100 |
11 | 3a17183529786 |
12 | 1469bb7137010 |
13 | 6b3c35253118 |
14 | 307c1b16063a |
15 | 16539a7d7e50 |
hex | b326df91e4c |
12311221313100 has 72 divisors (see below), whose sum is σ = 35650476848448. Its totient is φ = 3280226465600.
The previous prime is 12311221313089. The next prime is 12311221313117. The reversal of 12311221313100 is 131312211321.
It is a super-2 number, since 2×123112213131002 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 16930086 + ... + 17642285.
It is an arithmetic number, because the mean of its divisors is an integer number (495145511784).
Almost surely, 212311221313100 is an apocalyptic number.
12311221313100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
12311221313100 is an abundant number, since it is smaller than the sum of its proper divisors (23339255535348).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12311221313100 is a wasteful number, since it uses less digits than its factorization.
12311221313100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 34573575 (or 34573568 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 21.
Adding to 12311221313100 its reverse (131312211321), we get a palindrome (12442533524421).
The spelling of 12311221313100 in words is "twelve trillion, three hundred eleven billion, two hundred twenty-one million, three hundred thirteen thousand, one hundred".
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