Base | Representation |
---|---|
bin | 11011111111100010001100… |
… | …101000100101000001111111 |
3 | 121010220111221200210021221221 |
4 | 123333202030220211001333 |
5 | 112114042020304121343 |
6 | 1113501245315534211 |
7 | 34634433251546644 |
oct | 3377421450450177 |
9 | 533814850707857 |
10 | 123113302020223 |
11 | 36256070484729 |
12 | 119842238ba367 |
13 | 53906c4595498 |
14 | 2258a038cddcb |
15 | e376d5ce35ed |
hex | 6ff88ca2507f |
123113302020223 has 2 divisors, whose sum is σ = 123113302020224. Its totient is φ = 123113302020222.
The previous prime is 123113302020167. The next prime is 123113302020257. The reversal of 123113302020223 is 322020203311321.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-123113302020223 is a prime.
It is a super-2 number, since 2×1231133020202232 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (123113302020523) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61556651010111 + 61556651010112.
It is an arithmetic number, because the mean of its divisors is an integer number (61556651010112).
Almost surely, 2123113302020223 is an apocalyptic number.
123113302020223 is a deficient number, since it is larger than the sum of its proper divisors (1).
123113302020223 is an equidigital number, since it uses as much as digits as its factorization.
123113302020223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 123113302020223 its reverse (322020203311321), we get a palindrome (445133505331544).
The spelling of 123113302020223 in words is "one hundred twenty-three trillion, one hundred thirteen billion, three hundred two million, twenty thousand, two hundred twenty-three".
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