Base | Representation |
---|---|
bin | 10110111011101001… |
… | …01101011101010101 |
3 | 1011210000021212100121 |
4 | 23131310231131111 |
5 | 200203222021023 |
6 | 5353354311541 |
7 | 614043111415 |
oct | 133564553525 |
9 | 34700255317 |
10 | 12311517013 |
11 | 5248591a54 |
12 | 24771285b1 |
13 | 1212865813 |
14 | 84b14c645 |
15 | 4c0ca6d5d |
hex | 2ddd2d755 |
12311517013 has 2 divisors, whose sum is σ = 12311517014. Its totient is φ = 12311517012.
The previous prime is 12311516989. The next prime is 12311517047. The reversal of 12311517013 is 31071511321.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11954798244 + 356718769 = 109338^2 + 18887^2 .
It is an emirp because it is prime and its reverse (31071511321) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12311517013 - 229 = 11774646101 is a prime.
It is a super-2 number, since 2×123115170132 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12311517083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6155758506 + 6155758507.
It is an arithmetic number, because the mean of its divisors is an integer number (6155758507).
Almost surely, 212311517013 is an apocalyptic number.
It is an amenable number.
12311517013 is a deficient number, since it is larger than the sum of its proper divisors (1).
12311517013 is an equidigital number, since it uses as much as digits as its factorization.
12311517013 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 630, while the sum is 25.
The spelling of 12311517013 in words is "twelve billion, three hundred eleven million, five hundred seventeen thousand, thirteen".
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