Base | Representation |
---|---|
bin | 111001010101100011… |
… | …1101011011010010111 |
3 | 102202211010211010202011 |
4 | 1302223013223122113 |
5 | 4004132240013142 |
6 | 132322023125051 |
7 | 11616163511614 |
oct | 1625307533227 |
9 | 382733733664 |
10 | 123130001047 |
11 | 48245748249 |
12 | 1ba43ba3787 |
13 | b7c37b79b1 |
14 | 5d60d0d50b |
15 | 3309b78417 |
hex | 1cab1eb697 |
123130001047 has 2 divisors, whose sum is σ = 123130001048. Its totient is φ = 123130001046.
The previous prime is 123130001041. The next prime is 123130001147. The reversal of 123130001047 is 740100031321.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-123130001047 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (123130001041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61565000523 + 61565000524.
It is an arithmetic number, because the mean of its divisors is an integer number (61565000524).
Almost surely, 2123130001047 is an apocalyptic number.
123130001047 is a deficient number, since it is larger than the sum of its proper divisors (1).
123130001047 is an equidigital number, since it uses as much as digits as its factorization.
123130001047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 504, while the sum is 22.
Adding to 123130001047 its reverse (740100031321), we get a palindrome (863230032368).
The spelling of 123130001047 in words is "one hundred twenty-three billion, one hundred thirty million, one thousand, forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •