Base | Representation |
---|---|
bin | 111001010101100011… |
… | …1101011011011111011 |
3 | 102202211010211010212212 |
4 | 1302223013223123323 |
5 | 4004132240014042 |
6 | 132322023125335 |
7 | 11616163512116 |
oct | 1625307533373 |
9 | 382733733785 |
10 | 123130001147 |
11 | 4824574832a |
12 | 1ba43ba384b |
13 | b7c37b7a5a |
14 | 5d60d0d57d |
15 | 3309b78482 |
hex | 1cab1eb6fb |
123130001147 has 2 divisors, whose sum is σ = 123130001148. Its totient is φ = 123130001146.
The previous prime is 123130001047. The next prime is 123130001167. The reversal of 123130001147 is 741100031321.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 123130001147 - 214 = 123129984763 is a prime.
It is not a weakly prime, because it can be changed into another prime (123130001167) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61565000573 + 61565000574.
It is an arithmetic number, because the mean of its divisors is an integer number (61565000574).
Almost surely, 2123130001147 is an apocalyptic number.
123130001147 is a deficient number, since it is larger than the sum of its proper divisors (1).
123130001147 is an equidigital number, since it uses as much as digits as its factorization.
123130001147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 504, while the sum is 23.
Adding to 123130001147 its reverse (741100031321), we get a palindrome (864230032468).
The spelling of 123130001147 in words is "one hundred twenty-three billion, one hundred thirty million, one thousand, one hundred forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •